Re: How to utilize the CVTDQ2PD instruction?

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On Fri, 7 Sep 2012, Ian Lance Taylor wrote:

On Fri, Sep 7, 2012 at 5:05 AM, Henrik Mannerström
<henrik.mannerstrom@xxxxxxxxx> wrote:

If I understand the Intel reference correctly, the CVTDQ2PD should allow
me to convert two 64 bit integers into two 64 bit doubles in one blow.
How should I write this in gcc C/C++?

Program 1 uses casting to illustrate the point, it outputs 0 and 1.
Program 2 was my naive attempt to use vectorization, it outputs 0 and
4.94066e-324, which is _not_ what I intended.

  a.vd = __v2df(a.vi);

This is just a type cast of the vector as a whole.  It doesn't convert
the individual vector elements.

I always found it strange that vectors act like values everywhere, except for casts where they act like pointers. I understand this is convenient to allow calling intrinsics with vector types that don't exactly match, but it steals a good syntax that gcc's vector extensions can't use for true conversions.

--
Marc Glisse


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