Todd <todd.freed@xxxxxxxxx> writes:
> Hmm. I just need to have a function in my shared library, callable
> from the executable linked against the shared library, which I can
> also call
> from inside the shared library such that calls originating inside
> always
> invoke the one defined inside. What is the right way to achieve this, then?
Give the function in the library protected visibility, using gcc's
-fvisibility option or __attribute__ ((visibility ("protected"))).
Ian
