Re: sizeof( function )

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It is invalid to use sizeof() with a function
type expression (C99 '6.5.3.4 para. 1) and hence this code invokes
undefined behavior. gcc gives a warning if you compile with -pedantic,
but otherwise it apparently just returns 1;

But this is actually a BUG in gcc - look at 5.1.1.3.  The restriction
that sizeof may not have an argument that is function type is a
constraint, and therefore a breach requires a diagnostic.

There is no bug, as GCC prints a diagnostic just fine.
That's what -pedantic is for.


Segher


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