Re: sizeof( function )

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> It is invalid to use sizeof() with a function
> type expression (C99 '6.5.3.4 para. 1) and hence this code invokes
> undefined behavior.  gcc gives a warning if you compile with -pedantic,
> but otherwise it apparently just returns 1;
It's not quite that simple - look at footnote 84 :-(

Both function designators ('function names') and sizeof are weird,
in that they look like a value and a function, but aren't quite.

But this is actually a BUG in gcc - look at 5.1.1.3.  The restriction
that sizeof may not have an argument that is function type is a
constraint, and therefore a breach requires a diagnostic.


Regards,
Nick Maclaren,
University of Cambridge Computing Service,
New Museums Site, Pembroke Street, Cambridge CB2 3QH, England.
Email:  nmm1@xxxxxxxxx
Tel.:  +44 1223 334761    Fax:  +44 1223 334679

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