On Tue, Aug 02, 2005 at 10:05:37AM -0400, Daniel Jacobowitz wrote: > Yes, it does - well, it's implementation defined, but GCC has long > chosen the natural interpretation. C99 6.3.2.3, paragraph 5. This is > no different from that classic example, a pointer which escapes via > printf/scanf. > OK, thanks. That settles it then.
