> >Martin Kittel wrote: > >> // works fine >> A a; >> m_a = a; > >> // needs access to copy-constructor, why? >> m_a = A(); > >This is about reference binding of parameters. 8.5.3 says how references are initialized. in particular, 'a' is a non-temporary lvalue so the reference can be bound directly to it -- no copy ctor required. > I am not convinced. 8.5.3 is about reference initialization, while m_a is neither a reference nor are we talking about initialization here. To me, this is just plain assignment. So, I'd still say A() is plain construction of a temporary, and then according to 5.17 the copy assignment operator of m_a should be called (it is important here that we are not talking about initialization). Best wishes, Martin.
