This is very strange - still not working.
#include <sys/types.h>
#include <stdio.h>
#include <stdlib.h>
int main(int argc, char **argv) {
long long test;
test = 89126342536ll;
printf("Test d : %d \n", test);
printf("Test ll: %ll \n", test);
printf("Test L : %L \n", test);
printf("Test q : %q \n", test);
}And the result is: Test d : -1067970680 Test ll: % Test L : % Test q : %
I compile lik this:
g++ -L/usr/lib -o test test.cpp
If I try this:
gcc -L/usr/lib -o test test.cpp o receive an error:
/root/tmp/cc668HZr.o(.eh_frame+0x11): undefined reference to `__gxx_personality_v0'
collect2: ld returned 1 exit status
Thank you for your patience.
Brian Budge a scris:
ak, true true. Add ll to the end of the number.
For example, it would be 89126342536ll (those are Ls not 1s)
Brian
On Wed, 16 Feb 2005 13:58:04 +0200, Victor <victor@xxxxxxxx> wrote:
I have gcc version 3.4.1 compiled with long long support - but the result is the same. If I try A simple program like this: #include <stdio.h> #include <stdlib.h> int main(int argc, char **argv) { long long int test; test = 89126342536; } when I compile I get the following error: test.cpp: In function `int main(int, char**)': test.cpp:14: error: integer constant is too large for "long" type(long long seems to have no effect - it steel refers to simple long for some reason).
"gcc -v" output: Reading specs from /usr/lib/gcc/i586-mandrake-linux-gnu/3.4.1/specs Configured with: ../configure --prefix=/usr --libdir=/usr/lib --with-slibdir=/lib --mandir=/usr/share/man --infodir=/usr/share/info --enable-shared --enable-threads=posix --disable-checking --enable-long-long --enable-__cxa_atexit --enable-clocale=gnu --disable-libunwind-exceptions --enable-languages=c,c++,ada,f77,objc,java --host=i586-mandrake-linux-gnu --with-system-zlib Thread model: posix gcc version 3.4.1 (Mandrakelinux 10.1 3.4.1-4mdk)
Brian Budge a scris:
Ah, okay. long int in most 32 bit system is the same as int. Usually there is a type called long long which is 64 bits on 32 bit systems.
Brian
On Wed, 16 Feb 2005 13:19:05 +0200, Victor <victor@xxxxxxxx> wrote:
Thank you. The problem is that I don't know what type to declare the numeric variable. If I try A simple program like this: #include <stdio.h> #include <stdlib.h> int main(int argc, char **argv) { long int test; test = 89126342536; } when I compile I get the following error: test.cpp: In function `int main(int, char**)': test.cpp:14: error: integer constant is too large for "long" type
I know I must replace the line "long int test" with something else, but I don't know with what. Thank you.
Brian Budge a scris:
Hi Victor -
The number you specify is larger than can be held in a 32 bit integer. Use atoll instead.
Brian
On Wed, 16 Feb 2005 12:53:50 +0200, Victor <victor@xxxxxxxx> wrote:
I have this simple script:
#include <stdio.h> #include <stdlib.h> #include <string.h> int main(int argc, char **argv) { int test; char *numar = "89126342536"; test = atoi(numar); printf("Test: %d", test); }
I want to convert the string numar to integer. But the result - when I run the script is : Test: 2147483647 and I would expect: Test: 89126342536.
It seems that the number is too big. How can I solve this problem.
Thank you.
