Re: Array to integer problem(integer too long).

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I have gcc version 3.4.1 compiled with long long support - but the result is the same.
If I try A simple program like this:
#include <stdio.h>
#include <stdlib.h>
int main(int argc, char **argv) {
long long int test;
test = 89126342536;
}
when I compile I get the following error:
test.cpp: In function `int main(int, char**)':
test.cpp:14: error: integer constant is too large for "long" type(long long seems to have no effect - it steel refers to simple long for some reason).



"gcc -v" output:
Reading specs from /usr/lib/gcc/i586-mandrake-linux-gnu/3.4.1/specs
Configured with: ../configure --prefix=/usr --libdir=/usr/lib --with-slibdir=/lib --mandir=/usr/share/man --infodir=/usr/share/info --enable-shared --enable-threads=posix --disable-checking --enable-long-long --enable-__cxa_atexit --enable-clocale=gnu --disable-libunwind-exceptions --enable-languages=c,c++,ada,f77,objc,java --host=i586-mandrake-linux-gnu --with-system-zlib
Thread model: posix
gcc version 3.4.1 (Mandrakelinux 10.1 3.4.1-4mdk)


Brian Budge a scris:

Ah, okay.  long int in most 32 bit system is the same as int.  Usually
there is a type called long long which is 64 bits on 32 bit systems.

 Brian


On Wed, 16 Feb 2005 13:19:05 +0200, Victor <victor@xxxxxxxx> wrote:


Thank you.
The problem is that I don't know what type to declare the numeric variable.
If I try A simple program like this:
#include <stdio.h>
#include <stdlib.h>
int main(int argc, char **argv) {
   long int test;
   test = 89126342536;
}
when I compile I get the following error:
test.cpp: In function `int main(int, char**)':
test.cpp:14: error: integer constant is too large for "long" type

I know I must replace the line "long int test" with something else, but
I don't know with what.
Thank you.

Brian Budge a scris:



Hi Victor -

The number you specify is larger than can be held in a 32 bit integer.
Use atoll instead.

Brian


On Wed, 16 Feb 2005 12:53:50 +0200, Victor <victor@xxxxxxxx> wrote:




I have this simple script:

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int main(int argc, char **argv) {
  int test;
  char *numar = "89126342536";
  test = atoi(numar);
  printf("Test: %d", test);
}

I want to convert the string numar to integer.
But the result - when I run the script is :
Test: 2147483647
and I would expect:
Test: 89126342536.

It seems that the number is too big.
How can I solve this problem.

Thank you.

















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