Re: Array to integer problem(integer too long).

Victor <victor@xxxxxxxx> · Wed, 16 Feb 2005 13:19:05 +0200

Thank you.
The problem is that I don't know what type to declare the numeric variable.
If I try A simple program like this:
#include <stdio.h>
#include <stdlib.h>
int main(int argc, char **argv) {
   long int test;
   test = 89126342536;
}
when I compile I get the following error:
test.cpp: In function `int main(int, char**)':
test.cpp:14: error: integer constant is too large for "long" type

I know I must replace the line "long int test" with something else, but 
I don't know with what.

Thank you.

Brian Budge a scris:

Hi Victor -

The number you specify is larger than can be held in a 32 bit integer.
Use atoll instead.

 Brian

On Wed, 16 Feb 2005 12:53:50 +0200, Victor <victor@xxxxxxxx> wrote:

I have this simple script:

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int main(int argc, char **argv) {
   int test;
   char *numar = "89126342536";
   test = atoi(numar);
   printf("Test: %d", test);
}

I want to convert the string numar to integer.
But the result - when I run the script is :
Test: 2147483647
and I would expect:
Test: 89126342536.

It seems that the number is too big.
How can I solve this problem.

Thank you.