"Kevin P. Fleming" <kpfleming@xxxxxxxxxxxxxxx> writes: [...] | So, that leaves me back at my original quandary: I can create a | typedef of a function type, and I can use that typedef to declare | function pointers to hold addresses of compatible functions, but I | can't use the typedef to actually _declare_ those compatible functions sure, you can use it to declare the function itself. See the example I gave. But, yes, you can't use it to *define* it. Think about how you'd introduce the function parameters. -- Gaby
