"Kevin P. Fleming" <kpfleming@xxxxxxxxxxxxxxx> writes:
| Eljay Love-Jensen wrote:
| | > But the syntax of C doesn't have the language construct of "here's a
| > label (identifier), here's the type of that label, and here's it's
| > body".
<snip>
You mean like this:
typedef int F(int); F f; /* function "f" taking an int and returning an int. */
Well, I was wrong... it does not work. This specific example works, but only because the default return type for a function is "int".
If you try this with a typedef-ed function returning anything but int, you'll get errors from the compiler about incompatible definitions of the function.
So, that leaves me back at my original quandary: I can create a typedef of a function type, and I can use that typedef to declare function pointers to hold addresses of compatible functions, but I can't use the typedef to actually _declare_ those compatible functions (I have to write the prototype of the function to match the typedef, and if I don't do it correctly then any errors that the compiler finds will be at places where the function's address is assigned to a function pointer, not at the function definition itself). Bummer.
