Andy Shevchenko <andy.shevchenko@xxxxxxxxx> 於 2022年7月5日 週二 清晨5:52寫道：
>
> On Mon, Jul 4, 2022 at 9:27 AM ChiYuan Huang <u0084500@xxxxxxxxx> wrote:
> > ChiYuan Huang <u0084500@xxxxxxxxx> 於 2022年7月4日 週一 上午11:16寫道：
> > > Andy Shevchenko <andy.shevchenko@xxxxxxxxx> 於 2022年7月1日 週五 下午6:05寫道：
> > > > On Wed, Jun 29, 2022 at 4:23 AM cy_huang <u0084500@xxxxxxxxx> wrote:
>
> ...
>
> > > > > + *val = DIV_ROUND_UP(1000000, sample_time);
> > > >
> > > > USEC_PER_SEC ?
> > > >
> > > No, sample time is (vshunt convesion time + vbus conversion time) *
> > > average sample.
> > > And the sample freq returns the unit by HZ (sample frequency per second)
> > >
> > The 'sample time' is unit by micro-second like as you mentioned.
>
> Ah, then it should be MICRO, so we will get Hz.
>
> > > > > + return IIO_VAL_INT;
> > > > > +}
>
> ...
>
> > > > > + struct {
> > > > > + u16 vals[RTQ6056_MAX_CHANNEL];
> > > > > + int64_t timestamp;
> > > > > + } data __aligned(8);
> > > >
> > > > Hmm... alignment of this struct will be at least 4 bytes, but
> > > > shouldn't we rather be sure that the timestamp member is aligned
> > > > properly? Otherwise this seems fragile and dependent on
> > > > RTQ6056_MAX_CHANNEL % 4 == 0.
> > > >
> > > Yap, from the 'max channel', it already guarantee this struct will be
> > > aligned at lease 4.
> > > Actually, It can be removed.
>
> I think for the safest side it should be given to the timestamp member. No?
>
Sorry, following your comment, Why to use 'align' for the timestamp member?
the data member already guarantee 2 * 4 = 8 byte, then timestamp will
be 8 byte aligned, right?
what you mentioned is to put __aligned(8) only for timestamp.
I try to put aligned in two ways ( one is only for timestamp, another
is the whole struct). the result is the same.
>From my thinking, in this case, the struct is already 8 byte aligned
for timestamp member. don't you think to put 'aligned' is redundant?
> --
> With Best Regards,
> Andy Shevchenko
