Re: [bug?] echo -n does not work as described

[Bastian Bittorf <bittorf@xxxxxxxxxxxxxx>]

* Kevin Korb <kmk@xxxxxxxxxxxxxx> [12.11.2015 08:52]:
> $ echo -n testing
> - -n testing

in POSIX the '-n' switch (and -e) is undefined.
you can work around this via hijacking the call:

#!/bin/sh
echo()
{
	case "$1" in
		'-n')
			shift
			printf '%s' "$@"
		;;
		*)
			printf '%s\n' "$@"
		;;
	esac
}

echo foo
echo -n bar

if you really want to remove all the bashisms, it
can be a lot of work. dont blame dash for this, but
the script author. also consider using shellsheck.net
for this with the correct shebang.

bye, bastian
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