Re: [bug?] echo -n does not work as described

[Kevin Korb <kmk@xxxxxxxxxxxxxx>]

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Then why is the -n behaviour documented in the man page?

On 11/12/2015 03:10 AM, Bastian Bittorf wrote:
> * Kevin Korb <kmk@xxxxxxxxxxxxxx> [12.11.2015 08:52]:
>> $ echo -n testing - -n testing
> 
> in POSIX the '-n' switch (and -e) is undefined. you can work around
> this via hijacking the call:
> 
> #!/bin/sh echo() { case "$1" in '-n') shift printf '%s' "$@" ;; *) 
> printf '%s\n' "$@" ;; esac }
> 
> echo foo echo -n bar
> 
> if you really want to remove all the bashisms, it can be a lot of
> work. dont blame dash for this, but the script author. also
> consider using shellsheck.net for this with the correct shebang.
> 
> bye, bastian -- To unsubscribe from this list: send the line
> "unsubscribe dash" in the body of a message to
> majordomo@xxxxxxxxxxxxxxx More majordomo info at
> http://vger.kernel.org/majordomo-info.html
> 

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