On 4/27/14, 10:53 AM, Felipe Monteiro de Carvalho wrote: > Maybe my flaw is that to get the disk position I simply multiply the > block number by the size of a block ... I tryed to use > XFS_FSB_TO_DADDR instead but it gives 64 for block nr 8, which doesn't > make much sense, I'd expect 0x8000 if you have 4k blocks, filesystem block #8 is at 32k, or 64 512-byte "daddrs" so that is correct. A "DADDR" is in 512-byte units. -Eric _______________________________________________ xfs mailing list xfs@xxxxxxxxxxx http://oss.sgi.com/mailman/listinfo/xfs
