If you're not using an external program or script to run all your php
scripts, but want one script to execute another, then include or require
are the only methods that'll do the job.
Putting the include / require -part in the end of the first script is
exactly the same as running them both after each other.
Perhaps doing a header("Location: next-script.php"); will do what you
ask, but I don't know if that works without a browser!
Mike
Alf Stockton skrev:
Mikael Grön wrote:
Sidenote:
You can also do:
$dir = "folder/of/include/files";
$files = opendir($dir);
while ($file = readdir($file)):
if (substr($file,-4) == '.php'):
include_once($dir.'/'.$file);
endif;
endwhile;
but I wouldn't recommend it. :P
No neither would I recommend that solution and anyway I don't in any
way want to do an include.
If I was going to include then I may as well have coded that script
into the "calling" script and duplicate the stuff all over my system.
Maybe too much of my C programming background is showing but I just
want to call another script, the same as one would in C by calling
another program.
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