Have a 'look' at the object that is getting returned.
Insert 'asdf($obj_name);' as shown below and also put this script in your code.
function asdf($object, $where=false)
// Used for debugging. Reason for odd name is easy to type but also easy to find in code to get rid of
{
$type = gettype($object);
echo '<pre>';
echo '<br>### '.$where.' ### Type='.$type.' Value=';
if ($type == 'array') { print_r($object); } elseif ($type == 'object') { $class_vars = get_class_vars(get_class($object)); echo "Class vars:\n"; foreach ($class_vars as $name => $value) echo "$name : $value\n";
echo "Class methods:\n"; $class_methods = get_class_methods($object); foreach ($class_methods as $name => $value) echo "$name : $value\n";
echo "Object vars:\n"; $class_vars = get_object_vars($object); foreach ($class_vars as $name => $value) { echo "$name : $value\n"; if (gettype($value) == 'array') print_r($value); } } else { echo $object; }
echo '</pre>'; }
At 12:18 PM 1/07/2004, you wrote:
Thanks for the answers so far guys ... the thing that puzzles me is that the query definately works fine, because if I do this:
----------- function show_item($item) { $sublvl = $_GET['sub'];
$qry_item = query("select ITMLIST.*, GRPLIST.NAME AS SUBNAME from ITMLIST, GRPLIST where ITMLIST.ITEM_ID=$item AND GRPLIST.GROUP_ID = ITMLIST.PARENT_ID AND ITMLIST.PARENT_ID = $sublvl");
$obj_item = data($qry_item);
asdf($obj_name);
if ($obj_item){ print $obj_item->NAME; return $obj_item; } else { print "No data"; } } -------------
the output is fine, and when I uncomment the print line and call the script i do not get the "No data" message, as the object exists.
Could it be that it is just not possible to return the sort of object that ibase_fetch_object returns from a function ?
cheers,
Ben
> Ross Honniball wrote: > > I'm guessing your ibase_fetch_object($qry_result) call does not > successfully retrieve any data. It then returns false and your calling > script does nothing if false is returned.
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