Thanks for the answers so far guys ... the thing that puzzles me is
that the query definately works fine, because if I do this:
-----------
function show_item($item) {
$sublvl = $_GET['sub'];
$qry_item = query("select ITMLIST.*, GRPLIST.NAME AS SUBNAME from
ITMLIST, GRPLIST where ITMLIST.ITEM_ID=$item AND GRPLIST.GROUP_ID =
ITMLIST.PARENT_ID AND ITMLIST.PARENT_ID = $sublvl");
$obj_item = data($qry_item);
if ($obj_item){
print $obj_item->NAME;
return $obj_item;
} else {
print "No data";
}
}
-------------
the output is fine, and when I uncomment the print line and call the script
i do not get the "No data" message, as the object exists.
Could it be that it is just not possible to return the sort of object that
ibase_fetch_object returns from a function ?
cheers,
Ben
> Ross Honniball wrote:
>
> I'm guessing your ibase_fetch_object($qry_result) call does not
> successfully retrieve any data. It then returns false and your calling
> script does nothing if false is returned.
--
+++ Jetzt WLAN-Router für alle DSL-Einsteiger und Wechsler +++
GMX DSL-Powertarife zudem 3 Monate gratis* http://www.gmx.net/dsl
--
PHP Windows Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
