Rob Davis wrote:
> Pjotr Kourzanov wrote:
>> Luca Olivetti wrote:
>>> En/na Klaus Schmidinger ha escrit:
>>>> Udo Richter wrote:
>>>>> Pjotr Kourzanov wrote:
>>>>>> I am experiencing VDR errors when loading EPG via SVDRP. If the EPG
>>>>>> data to
>>> ...
>>>>
>>>> I have recently sent the attached patch to Thomas Koch
>>>> <tom@xxxxxxxxxx>.
>>>> It dramatically speeds up getting EPG information from VDR.
>>>
>>> I think the OP problem is the reverse: getting EPG data into vdr, not
>>> out of it.
>>>
>>> Bye
>>
>> Indeed, I was referring to the problem of loading the data to VDR.
>> Tweaking the watchdog
>> timer looks like a dirty workaround to me - the value depending on
>> amount of EPG data to
>> be loaded divided by the speed at which this data could be transferred
>> to VDR (do we assume
>> loopback access, or ethernet? maybe wireless or WAN/VPN access?).
>>
>> I have neither investigated the problem deeper yet (just found a way
>> to split the EPG data into
>> parts), nor looked in the source code. Is it so difficult to convince
>> the watchdog that while SVDR thread is busy it is actually doing
>> useful work?
>
> Pjotr,
>
> How did you split the information up?
See script attached (given stdin, creates epg.[0-9]* files of ~3megs,
without overwriting).
>
> I have a 17MB xmltv file which I would like to upload into VDR.
>
> Is it possible to adjust xmltv2vdr.pl to split the xmltv epg into parts
> too?
>
Maybe. I found xmltv2vdr just too slow - it took ~9 hours to output
17MB of VDR epg.data. The XML was btw. ~54MB.
> My python knowledge is limited, but I am willing to have a stab at it.
>
xmltv2vdr.pl is perl:-( But if you know AWK, I've posted my version
of xmltv2epg on this list that takes ~40 minutes on the same data:-)
Also, it takes extra info like credits into VDR's epg...
Regards,
Pjotr
-------------- next part --------------
#!/usr/bin/awk -f
BEGIN {
max=3*1024*1024
if (!base) base="epg."
n=1
advance()
size=0
}
/^[CEeTSDX]/ { size+=length }
{ print > base n }
/^c/ {
if (size>max) {
advance()
size=0
}
}
func advance() {
while (!system("stat " base n " >/dev/null 2>&1"))
n++
}
