On 2020/8/30 1:16, Laurent Pinchart wrote:
On Sat, Aug 29, 2020 at 02:10:20PM +0200, Pavel Machek wrote:
Hi!
The value av7110->debi_virt is stored in DMA memory, and it is assigned
to data, and thus data[0] can be modified at any time by malicious
hardware. In this case, "if (data[0] < 2)" can be passed, but then
data[0] can be changed into a large number, which may cause buffer
overflow when the code "av7110->ci_slot[data[0]]" is used.
To fix this possible bug, data[0] is assigned to a local variable, which
replaces the use of data[0].
I'm pretty sure hardware capable of manipulating memory can work
around any such checks, but...
+++ b/drivers/media/pci/ttpci/av7110.c
@@ -424,14 +424,15 @@ static void debiirq(unsigned long cookie)
case DATA_CI_GET:
{
u8 *data = av7110->debi_virt;
+ u8 data_0 = data[0];
- if ((data[0] < 2) && data[2] == 0xff) {
+ if (data_0 < 2 && data[2] == 0xff) {
int flags = 0;
if (data[5] > 0)
flags |= CA_CI_MODULE_PRESENT;
if (data[5] > 5)
flags |= CA_CI_MODULE_READY;
- av7110->ci_slot[data[0]].flags = flags;
+ av7110->ci_slot[data_0].flags = flags;
This does not even do what it says. Compiler is still free to access
data[0] multiple times. It needs READ_ONCE() to be effective.
Yes, it seems quite dubious to me. If we *really* want to guard against
rogue hardware here, the whole DMA buffer should be copied. I don't
think it's worth it, a rogue PCI device can do much more harm.
From the original driver code, data[0] is considered to be bad and thus
it should be checked, because the content of the DMA buffer may be
problematic.
Based on this consideration, data[0] can be also modified to bypass the
check, and thus its value should be copied to a local variable for the
check and use.
I agree with Pavel that the compiler optimization may drop the copying
operation, and thus READ_ONCE() should be used here.
I will submit a v2 patch soon.
Best wishes,
Jia-Ju Bai
