From: Vegard Nossum <vegard.nossum@xxxxxxxxx> Date: Fri, 20 May 2016 14:04:54 +0200 > Just out of curiosity, was this observed in practice? I could be > wrong, but I was under the impression that using designated > initializers would zero the rest of the struct, including padding. I compiled testcases and found that the compiler does not zero out padding when using designated initializers. You can do the same. For example, on sparc 32-bit, this code: struct foo { int a; short b; int c; }; extern void foo(struct foo *); void bar(void) { struct foo f = { .a = 1, .b = 2, .c = 3 }; foo(&f); } gives: mov 1, %g1 st %g1, [%fp-12] mov 2, %g1 sth %g1, [%fp-8] mov 3, %g1 st %g1, [%fp-4] It does not initialize the padding between 'b' and 'c'. -- To unsubscribe from this list: send the line "unsubscribe stable" in the body of a message to majordomo@xxxxxxxxxxxxxxx More majordomo info at http://vger.kernel.org/majordomo-info.html