On Wed, Oct 14, 2015 at 11:04:19PM +0200, Peter Zijlstra wrote: > On Wed, Oct 14, 2015 at 01:19:17PM -0700, Paul E. McKenney wrote: > > Suppose we have something like the following, where "a" and "x" are both > > initially zero: > > > > CPU 0 CPU 1 > > ----- ----- > > > > WRITE_ONCE(x, 1); WRITE_ONCE(a, 2); > > r3 = xchg(&a, 1); smp_mb(); > > r3 = READ_ONCE(x); > > > > If xchg() is fully ordered, we should never observe both CPUs' > > r3 values being zero, correct? > > > > And wouldn't this be represented by the following litmus test? > > > > PPC SB+lwsync-RMW2-lwsync+st-sync-leading > > "" > > { > > 0:r1=1; 0:r2=x; 0:r3=3; 0:r10=0 ; 0:r11=0; 0:r12=a; > > 1:r1=2; 1:r2=x; 1:r3=3; 1:r10=0 ; 1:r11=0; 1:r12=a; > > } > > P0 | P1 ; > > stw r1,0(r2) | stw r1,0(r12) ; > > lwsync | sync ; > > lwarx r11,r10,r12 | lwz r3,0(r2) ; > > stwcx. r1,r10,r12 | ; > > bne Fail0 | ; > > mr r3,r11 | ; > > Fail0: | ; > > exists > > (0:r3=0 /\ a=2 /\ 1:r3=0) > > > > I left off P0's trailing sync because there is nothing for it to order > > against in this particular litmus test. I tried adding it and verified > > that it has no effect. > > > > Am I missing something here? If not, it seems to me that you need > > the leading lwsync to instead be a sync. > > So the scenario that would fail would be this one, right? > > a = x = 0 > > CPU0 CPU1 > > r3 = load_locked (&a); > a = 2; > sync(); > r3 = x; > x = 1; > lwsync(); > if (!store_cond(&a, 1)) > goto again > > > Where we hoist the load way up because lwsync allows this. That scenario would end up with a==1 rather than a==2. > I always thought this would fail because CPU1's store to @a would fail > the store_cond() on CPU0 and we'd do the 'again' thing, re-issuing the > load and now seeing the new value (2). The stwcx. failure was one thing that prevented a number of other misordering cases. The problem is that we have to let go of the notion of an implicit global clock. To that end, the herd tool can make a diagram of what it thought happened, and I have attached it. I used this diagram to try and force this scenario at https://www.cl.cam.ac.uk/~pes20/ppcmem/index.html#PPC, and succeeded. Here is the sequence of events: o Commit P0's write. The model offers to propagate this write to the coherence point and to P1, but don't do so yet. o Commit P1's write. Similar offers, but don't take them up yet. o Commit P0's lwsync. o Execute P0's lwarx, which reads a=0. Then commit it. o Commit P0's stwcx. as successful. This stores a=1. o Commit P0's branch (not taken). o Commit P0's final register-to-register move. o Commit P1's sync instruction. o There is now nothing that can happen in either processor. P0 is done, and P1 is waiting for its sync. Therefore, propagate P1's a=2 write to the coherence point and to the other thread. o There is still nothing that can happen in either processor. So pick the barrier propagate, then the acknowledge sync. o P1 can now execute its read from x. Because P0's write to x is still waiting to propagate to P1, this still reads x=0. Execute and commit, and we now have both r3 registers equal to zero and the final value a=2. o Clean up by propagating the write to x everywhere, and propagating the lwsync. And the "exists" clause really does trigger: 0:r3=0; 1:r3=0; [a]=2; I am still not 100% confident of my litmus test. It is quite possible that I lost something in translation, but that is looking less likely. > > Of course, if I am not missing something, then this applies also to the > > value-returning RMW atomic operations that you pulled this pattern from. > > If so, it would seem that I didn't think through all the possibilities > > back when PPC_ATOMIC_EXIT_BARRIER moved to sync... In fact, I believe > > that I worried about the RMW atomic operation acting as a barrier, > > but not as the load/store itself. :-/ > > AARGH64 does something very similar; it does something like: > > ll > ... > sc-release > > mb > > Which I assumed worked for the same reason, any change to the variable > would fail the sc, and we go for round 2, now observing the new value. I have to defer to Will on this one. You are right that ARM and PowerPC do have similar memory models, but there are some differences. Thanx, Paul
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