sorry to ask questions again and again.
I am new to rpm packaging.
I am trying to create one RPM package for my daemon application in Fedora 10.
daemon application contains ,
1. daemon.c
2. daemon.h
3. list.c
4.list.h
5.makefile.
So , I am just tar the daemon application as "daemon.tar.gz".
I put this daemon.tar.gz in /home/user/rpmbuild/SOURCES directory.
I am creating spec filr and put it in /home/user/rpmbuild/SPECS directory.
Now, I am tying to create binary RPM for my application. I am in x86_64 architecture.
when I run rpmbuild -bs daemon-1.spec and then rpmbuild -bb daemon-1.spec
only source rpm created. Binary RPM is not created.
How to cretae binary RPM for my application.
MY spec file is,
[SPEC]
Summary: This Package install Daemon application
Name: daemon
Version:1
Release:1
License: GPL
Group: Applications/System
Source:daemon.tar.gz
BuildRoot: /home/nco_user/rpmbuild/tmp
BuildArch:noarch
Packager:S.J.Ram
%define destdir /home/nco_user/rpmbuild/builddir
%description
This Package install Daemon application
%prep
%setup -qn %{name}
%build
make
%install
#rm -rf $RPM_BUILD_ROOT
make install
%clean
rm -rf $RPM_BUILD_ROOT
%files
%defattr(-,root,root,-)
%{_tmppath}/daemon
[/SPEC]
please guide me to create binary rpm.
Do I need to change SPEC file?.
thank you.
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