Mr.Sean is correct.
...a litle bit from my side...
[vipin@vipin ~]$ grep -v age testsort.txt | awk '{print $2}' | sort -r
On 6/19/06, Miner, Jonathan W (CSC) (US SSA)
<jonathan.w.miner@xxxxxxxxxxxxxx> wrote:
-----Original Message-----
From: redhat-list-bounces@xxxxxxxxxx on behalf of Aimin Yan
Sent: Sat 06/17/2006 02:23 PM
To: redhat-list@xxxxxxxxxx
Cc:
Subject: sort
i have a file, I want to sort this file based on the 2nd column, and start
from 1st row.how can
I do use sort command to do in redhat linux.
for example, this is file I want to sort
name age income
trorry 34 344
aimin 36 345
shihe 23 3667
Aimin
-----------------------------
Lots of possible answers to this, here is one that preserves the header line, and the rest of the file contents:
f={filename}
(head -1 $f; awk 'BEGIN {getline} {print $0}' $f | sort -k2 -n) > $f.new
mv $f.new $f
This depends on having a single title line in the field, a better method, in my opinion, is to use the pound sign (#) to mark comments. The code then becomes:
f={filename}
(grep '^#' $f; grep -v '^#' $f | sort -k2 -n) > $f.new
mv $f.new $f
Enjoy
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