On Sun, 16 May 2004 09:07:43 -0500, Mike Vanecek wrote: > Given this text in packet.test2 > > May 16 21:35:35 www kernel: icmp_try IN=eth0 OUT= > MAC=00:d0:09:3d:69:81:00:04:5a:ef:5e:1d:08:00 SRC=144.232.20.162 > DST=192.168.1.95 LEN=56 TOS=0x00 PREC=0xC0 TTL=241 ID=57923 PROTO=ICMP TYPE=11 > CODE=0 [SRC=66.76.12.5 DST=200.216.94.217 LEN=40 TOS=0x00 PREC=0x00 TTL=1 > ID=25653 PROTO=TCP INCOMPLETE [8 bytes] ] > May 16 21:54:39 www kernel: icmp_try IN=eth0 OUT= > MAC=00:d0:09:3d:69:81:00:04:5a:ef:5e:1d:08:00 SRC=144.232.7.98 > DST=192.168.1.95 LEN=56 TOS=0x00 PREC=0x00 TTL=239 ID=0 PROTO=ICMP TYPE=11 > CODE=0 [SRC=66.76.12.5 DST=200.222.69.36 LEN=40 TOS=0x00 PREC=0x00 TTL=1 > ID=62986 PROTO=TCP INCOMPLETE [8 bytes] ] > > Why does this command > > $ grep -i "`date '+%b %_d'`" packet.test2 | sed -re > 's/.*SRC=([0-9]+\.[0-9]+\.[0-9]+\.[0-9]).*/\1/' > 66.76.12.5 > 66.76.12.5 > > pick up the second SRC rather than the first? > > My brain, eyes, or both are just not finding it... Because the regular expression .* at the beginning matches the longest substring possible. That includes everything up to the second SRC= -- redhat-list mailing list unsubscribe mailto:redhat-list-request@xxxxxxxxxx?subject=unsubscribe https://www.redhat.com/mailman/listinfo/redhat-list
