On Sun, 16 May 2004 10:12:21 -0400, Jason Dixon wrote > On May 16, 2004, at 10:07 AM, Mike Vanecek wrote: > > > Given this text in packet.test2 > > > > May 16 21:35:35 www kernel: icmp_try IN=eth0 OUT= > > MAC=00:d0:09:3d:69:81:00:04:5a:ef:5e:1d:08:00 SRC=144.232.20.162 > > DST=192.168.1.95 LEN=56 TOS=0x00 PREC=0xC0 TTL=241 ID=57923 PROTO=ICMP > > TYPE=11 > > CODE=0 [SRC=66.76.12.5 DST=200.216.94.217 LEN=40 TOS=0x00 PREC=0x00 > > TTL=1 > > ID=25653 PROTO=TCP INCOMPLETE [8 bytes] ] > > May 16 21:54:39 www kernel: icmp_try IN=eth0 OUT= > > MAC=00:d0:09:3d:69:81:00:04:5a:ef:5e:1d:08:00 SRC=144.232.7.98 > > DST=192.168.1.95 LEN=56 TOS=0x00 PREC=0x00 TTL=239 ID=0 PROTO=ICMP > > TYPE=11 > > CODE=0 [SRC=66.76.12.5 DST=200.222.69.36 LEN=40 TOS=0x00 PREC=0x00 > > TTL=1 > > ID=62986 PROTO=TCP INCOMPLETE [8 bytes] ] > > > > Why does this command > > > > $ grep -i "`date '+%b %_d'`" packet.test2 | sed -re > > 's/.*SRC=([0-9]+\.[0-9]+\.[0-9]+\.[0-9]).*/\1/' > > 66.76.12.5 > > 66.76.12.5 > > > > pick up the second SRC rather than the first? > > I'm not a sed expert, but I'm guessing it's behaving "greedy", > similar to perl regex. The first SRC actually falls within the ".*" > portion of your match, and the last match is what counts. I thought it would pick up the first? If I change the second SRC to SRX, then it does pick up the first one. What do I need to specify to make it pick up the first one? -- redhat-list mailing list unsubscribe mailto:redhat-list-request@xxxxxxxxxx?subject=unsubscribe https://www.redhat.com/mailman/listinfo/redhat-list
