Hi,
Sorry, I make a fault: the right command is:
fuser -u SO* | awk ' { print $x } '
For me, it is the end of the day!
Cheers,
Yann
-----Message d'origine-----
De : Yann Garcia [mailto:yann.garcia@xxxxxxxxxxxx]
Envoyé : jeudi 22 avril 2004 18:10
À : 'General Red Hat Linux discussion list'
Objet : RE : need a sed guru to help me strip out words
Hi,
I use awk, it's more easy :
fuser -u SO* | awk ' print $x '
where $x is the column number you want to extract.
(Ex. Ls -l | awk ' print $3 ' returns the list of the 'user' field).
Cheers,
Yann
-----Message d'origine-----
De : redhat-list-bounces@xxxxxxxxxx
[mailto:redhat-list-bounces@xxxxxxxxxx] De la part de Eric Wood
Envoyé : jeudi 22 avril 2004 17:41
À : Red Hat List
Objet : need a sed guru to help me strip out words
# fuser -u SO*
SODEI: 8952(whse) 23496(lhoover) 28450(recept) 28845(dschuetterle)
30835(awalter)
SOLSI: 8952(whse) 23496(lhoover) 28450(recept) 28845(dschuetterle)
30835(awalter) 20242(ewood)
I need a sed formula to just list out the user names
# fuser -u SO* | sed 'something' | uniq
whse
lhoover
recept
dschuetterle
awalter
ewood
Any help is appreciated!
-eric wood
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