Hi, I use awk, it's more easy : fuser -u SO* | awk ' print $x ' where $x is the column number you want to extract. (Ex. Ls -l | awk ' print $3 ' returns the list of the 'user' field). Cheers, Yann -----Message d'origine----- De : redhat-list-bounces@xxxxxxxxxx [mailto:redhat-list-bounces@xxxxxxxxxx] De la part de Eric Wood Envoyé : jeudi 22 avril 2004 17:41 À : Red Hat List Objet : need a sed guru to help me strip out words # fuser -u SO* SODEI: 8952(whse) 23496(lhoover) 28450(recept) 28845(dschuetterle) 30835(awalter) SOLSI: 8952(whse) 23496(lhoover) 28450(recept) 28845(dschuetterle) 30835(awalter) 20242(ewood) I need a sed formula to just list out the user names # fuser -u SO* | sed 'something' | uniq whse lhoover recept dschuetterle awalter ewood Any help is appreciated! -eric wood -- redhat-list mailing list unsubscribe mailto:redhat-list-request@xxxxxxxxxx?subject=unsubscribe https://www.redhat.com/mailman/listinfo/redhat-list -- redhat-list mailing list unsubscribe mailto:redhat-list-request@xxxxxxxxxx?subject=unsubscribe https://www.redhat.com/mailman/listinfo/redhat-list
