On 11/20/2013 11:05 AM, Andrea Mazzoleni wrote: > > For the first row with j=0, I use xi = 2^-i and y0 = 0, that results in: > How can xi = 2^-i if x is supposed to be constant? That doesn't mean that your approach isn't valid, of course, but it might not be a Cauchy matrix and thus needs additional analysis. > row j=0 -> 1/(xi+y0) = 1/(2^-i + 0) = 2^i (RAID-6 coefficients) > > For the next rows with j>0, I use yj = 2^j, resulting in: > > rows j>0 -> 1/(xi+yj) = 1/(2^-i + 2^j) Even more so here... 2^-i and 2^j don't seem to be of the form xi and yj respectively. -hpa -- To unsubscribe from this list: send the line "unsubscribe linux-raid" in the body of a message to majordomo@xxxxxxxxxxxxxxx More majordomo info at http://vger.kernel.org/majordomo-info.html
