Hi guys,
I just discovered this when I was about to do a disk transfer:
[edited for brevity]
$ sudo fdisk -l
Disk /dev/sdc: 2000.4 GB, 2000397852160 bytes
255 heads, 63 sectors/track, 243201 cylinders, total 3907027055 sectors
Units = sectors of 1 * 512 = 512 bytes
Sector size (logical/physical): 512 bytes / 4096 bytes
I/O size (minimum/optimal): 4096 bytes / 4096 bytes
Disk identifier: 0x00027892
Disk /dev/sdd: 2000.4 GB, 2000398934016 bytes
255 heads, 63 sectors/track, 243201 cylinders, total 3907029168 sectors
Units = sectors of 1 * 512 = 512 bytes
Sector size (logical/physical): 512 bytes / 512 bytes
I/O size (minimum/optimal): 512 bytes / 512 bytes
Disk identifier: 0x00000000
$ sudo smartctl -a /dev/sdc
Model Family: Seagate Barracuda (SATA 3Gb/s, 4K Sectors)
Device Model: ST2000DM001-1CH164
Firmware Version: CC43
User Capacity: 2,000,397,852,160 bytes [2.00 TB]
Sector Sizes: 512 bytes logical, 4096 bytes physical
ATA Version is: 8
ATA Standard is: ATA-8-ACS revision 4
$ sudo smartctl -a /dev/sdd
Model Family: Seagate Barracuda LP
Device Model: ST32000542AS
Firmware Version: CC34
User Capacity: 2,000,398,934,016 bytes [2.00 TB]
Sector Size: 512 bytes logical/physical
ATA Version is: 8
ATA Standard is: ATA-8-ACS revision 4
These are from the same manufacturer! Interestingly, the larger drive
is actually the older one!
Is the "standardization" not a fixed value but a minimum? If so, what
is that actual minimum? If it's an actual 2 terabyte (2x10^12), then I
suppose they're both technically over, but that means that we can't just
simply create partitions that fill the space and expect to be able to
transfer them later. :-(
Cheers,
Tudor.
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