Hi, I described on this list (a few days ago) how I physically removed one of 2 drives from a raid 1 array. I then took it to another computer to use it as a second copy of the data. That worked fine, although I described at that time that my linux box would not boot normally until I ran mdadm -A --run /dev/md0 /dev/hdb1 with the --run option as the raid 1 would not start in the degraded state otherwise. I was wondering. imagine I have /dev/md0 composed of /dev/hdb1 and /dev/hdg1 What is the effect of the command mdadm --manage /dev/md0 -f /dev/hdg1 Ie: If I "fail" the drive in this way: 1) will the remainder of the array (ie /dev/md0 composed of /dev/hdb1) now boot without the --run being added in? 2) Will I still be able to take the drive /dev/hdg1 and use it on another machine as a copy of the data from the array? 3) If the answer to 2 is no, should I do a) remove drive /dev/hdg1 physically (machine off) b) then after booting without /dev/hdg1 via the --run run the command mdadm --manage /dev/md0 -f /dev/hdg1 (even though it is not on the machine... then will it boot without the --run added in. thanks, I am simply not sure of what -f does... Thanks, Mitchell - To unsubscribe from this list: send the line "unsubscribe linux-raid" in the body of a message to majordomo@xxxxxxxxxxxxxxx More majordomo info at http://vger.kernel.org/majordomo-info.html
