Re: About PDO::fetchObject

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Something like this should get you started

<?php


// NOT TESTED !!!

class SimpleMapper
{

    private $metadata = array();
    private $stmt;

    public function __construct(PDOStatement $stmt, array $metadata)
    {
        $this->stmt = $stmt;
        $this->metadata = $metadata;
    }

    public function map()
    {
        $databaseData = $this->stmt->fetchObject();
        $r = new \ReflectionClass($this->metadata['class']);
        $obj = $r->newInstanceWithoutConstructor();

        foreach ($this->metadata['c2p'] as $col => $property) {
            $val = $databaseData->$col;
            $type = $property['type'] ?: 'string';
            settype($val, $type);

            $prop = $r->getProperty($property['name']);
            $prop->setAccessible(true);
            $prop->setValue($val);
        }

        return $obj;
    }

}

// usage

class Item {
    public $id;
    public $name;
    public $description;
}

$mapper = new SimpleMapper($stmt, array(
    // the class where we want to map the database data
    'class' => 'Item',
    // database column to object property mapping metadata
    'c2p' => array(
        'ItemID' => array('name' => 'id', 'type' => 'int'),
        'ItemName' => array('name' => 'name', 'type' => 'string'),
        'ItemDescription' => array('name' => 'description', 'type' =>
'string')
    )
));

$item = $mapper->map();

On Thu, Jun 11, 2015 at 9:26 AM, Octopus Puras <zlk1214@xxxxxxxxx> wrote:

> I have a MySQL table, whose name is Items:
> ItemID ItemName ItemDescription
>
> I also have a PHP class:
> class Item {
>   public $id;
>   public $name;
>   public $description;
> }
>
> If I execute $stmt->fetchObject(), I will get an object with fields of
> ItemID, ItemName, etc. But I want to adapt the name of the fields to the
> Item class. What should I do?
>

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