Re: VAR_DUMP INTO PHP VARIABLES

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On Thu, Jun 19, 2014 at 10:09 AM, Toby Hart Dyke <toby@xxxxxxxxxxxx> wrote:

>
>
> My error! This:
>
>
> $responseCode = $result[return]['responsecode'];
>
> should have been
>
>
> $responseCode = $result['return']['responsecode'];
>
>
> The other responses have been rather more elegant, though I think my
> solution is a little more readable - i.e., I had to think about what was
> happening for those ones!
>
>   Toby
>
>
> On 6/19/2014 9:50 AM, Oriole Computing wrote:
>
>> Hi Toby,
>>
>> my response is in variable $result so i run the code as below
>>
>> $responseCode = $result[return]['responsecode'];
>>
>> but getting this error: PHP Parse error:  syntax error, unexpected
>> T_RETURN, expecting ']
>>
>> Warm Regards
>>
>>
>>
>> *SUPPORT TEAMORIOLE COMPUTING*
>>
>> *1938 B1 MUNGWI ROAD*
>>
>> *LUSAKAZAMBIA*
>>
>> *Skype:* oriolecomputing | *Url:* oriolecomputing.blogspot.com
>> <http://generalcomputing.blogspot.com/>
>>
>>
>> On Thu, Jun 19, 2014 at 12:23 PM, Pritoj Singh <pritojs@xxxxxxxxx> wrote:
>>
>>  foreach($arr['return'] as $key=>$val){
>>> $$key=$val;
>>> }
>>>
>>>
>>> On Thu, Jun 19, 2014 at 3:48 PM, Toby Hart Dyke <toby@xxxxxxxxxxxx>
>>> wrote:
>>>
>>>  If you have the response in a variable, $response:
>>>>
>>>> $responseCode = $response[return]['responsecode'];
>>>> $responseMessage = $response[return]['responseMessage'];
>>>> $transactionID = $response[return]['transactionID'];
>>>>
>>>>
>>>>
>
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