Re: VAR_DUMP INTO PHP VARIABLES

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My error! This:

$responseCode = $result[return]['responsecode'];

should have been

$responseCode = $result['return']['responsecode'];


The other responses have been rather more elegant, though I think my solution is a little more readable - i.e., I had to think about what was happening for those ones!

  Toby

On 6/19/2014 9:50 AM, Oriole Computing wrote:
Hi Toby,

my response is in variable $result so i run the code as below

$responseCode = $result[return]['responsecode'];

but getting this error: PHP Parse error:  syntax error, unexpected
T_RETURN, expecting ']

Warm Regards



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On Thu, Jun 19, 2014 at 12:23 PM, Pritoj Singh <pritojs@xxxxxxxxx> wrote:

foreach($arr['return'] as $key=>$val){
$$key=$val;
}


On Thu, Jun 19, 2014 at 3:48 PM, Toby Hart Dyke <toby@xxxxxxxxxxxx> wrote:

If you have the response in a variable, $response:

$responseCode = $response[return]['responsecode'];
$responseMessage = $response[return]['responseMessage'];
$transactionID = $response[return]['transactionID'];




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