Dear List -
Here is another problem I am having with prepared statements. The last
one was INSERT, this one is SELECT.
Here is the database:
mysql> describe Intake3;
+--------+-------------+------+-----+---------+-------+
| Field | Type | Null | Key | Default | Extra |
+--------+-------------+------+-----+---------+-------+
| Site | varchar(6) | NO | PRI | | |
| MedRec | int(6) | NO | PRI | NULL | |
| Fname | varchar(15) | YES | | NULL | |
| Lname | varchar(30) | YES | | NULL | |
| Phone | varchar(30) | YES | | NULL | |
| Height | int(4) | YES | | NULL | |
| Sex | char(7) | YES | | NULL | |
| Hx | text | YES | | NULL | |
| Bday | date | YES | | NULL | |
| Age | int(3) | YES | | NULL | |
+--------+-------------+------+-----+---------+-------+
10 rows in set (0.00 sec)
Here is my code:
// Prepare statement
$stmt = mysqli_stmt_init($cxn);
$sql11 = "SELECT 'Fname', 'Lname', 'Phone', Height, Hx, Bday, Age
FROM Intake3 where 1 and (MedRec = ?) and (Site = ?) and (Sex = ?)";
// Allocates and initializes a statement object suitable for
mysqli_stmt_prepare().
// Prepare statement, bind result variables, execute and place results
into bound result variables
mysqli_stmt_prepare($stmt, $sql11);
mysqli_stmt_execute($stmt);
mysqli_stmt_bind_result($stmt, $Site, $MedRec, $Fname, $Lname,
$Phone, $Height, $Sex, $Hx, $Bday, $Age); //The error is in this statement.
while (mysqli_stmt_fetch($stmt)) {
printf("%s %s %s %s %s %s %s %s %s %s \n", $Site, $MedRec,
$Fname, $Lname, $Phone, $Height, $Sex, $Hx, $Bday, $Age);
}
I get no output from the printf statement.
I receive the following error:
Warning: mysqli_stmt_bind_result(): Number of bind variables doesn't match number of fields in prepared statement.
The query, with the values inserted, works on the command line
Help and advice, please.
Ethan
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