Dear Ron
Try this
===================
SELECT `cross_reference_article_2`
FROM `frequently_accessed_passages_of_scripture_cross_reference`
WHERE `cross_reference_article_1` = 1
UNION ALL
SELECT `cross_reference_article_1`
FROM `frequently_accessed_passages_of_scripture_cross_reference`
WHERE `cross_reference_article_2` = 1
===================
I have removed the first line and the last line of your query
============
regds
amit
"The difference between fiction and reality? Fiction has to make sense."
On Sun, Jul 17, 2011 at 10:14 AM, Ron Piggott <
ron.piggott@xxxxxxxxxxxxxxxxxx> wrote:
>
> I am trying to setup a cross reference database query for the first time.
> What I am trying to do is have a table with the structure:
>
>
>
> CREATE TABLE IF NOT EXISTS
> `frequently_accessed_passages_of_scripture_cross_reference` (
> `reference` int(5) NOT NULL AUTO_INCREMENT,
> `cross_reference_article_1` int(3) NOT NULL,
> `cross_reference_article_2` int(3) NOT NULL,
> PRIMARY KEY (`reference`)
> ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=1 ;
>
>
>
> If the content theme (based on auto_increment values) is listed in either
> cross_reference_article_1 OR cross_reference_article_2 then the counter part
> article will be a result so I may offer an “Also available:” type link on
> the web page. My attempt at the UNION ALL query is below. I am receiving
> the error “Every derived table must have its own alias” I am unsure of how
> to interpret this and correct the situation. Thanks for your help. Ron
>
>
>
> SELECT cross_reference_article_2 FROM
>
> (
>
> SELECT `cross_reference_article_2` FROM
> `frequently_accessed_passages_of_scripture_cross_reference` WHERE
> `cross_reference_article_1` = 1
>
> ) UNION ALL (
>
> SELECT `cross_reference_article_1` FROM
> `frequently_accessed_passages_of_scripture_cross_reference` WHERE
> `cross_reference_article_2` = 1
>
> )
>
> AS cross_reference_view_result
>
>
> The Verse of the Day
> “Encouragement from God’s Word”
> http://www.TheVerseOfTheDay.info
