Thank you for this as well.
Question? What part is "in_array" playing?
Is it comparing $req_user_level to array()?
Because the text "Guest", etc.. is not in $req_user_level on the
database.
In other words, is it checking the value of $req_user_level to see if
"Guest" is in it?
Karl
On Jan 25, 2010, at 1:32 PM, Peter Beckman wrote:
On Mon, 25 Jan 2010, Karl DeSaulniers wrote:
Hello List,
Trying to learn the right way to code this line.
Can anyone tell me if I am doing this the right way?
if $req_user_level == 0 || 1 || 2 || 3 || 4 || 5 || 6 || 7 || 8 ||
9 ? "Guest" || "Regular User" || "Intl. User" || "Contractor" ||
"Employee" || "Sales" || "Investor" || "Human Resources" ||
"Administrator";
I am wanting to stray from the if(foo == bar) { routine. ;)
if (in_array($req_user_level, array
(0,1,2,3,4,5,6,7,8,9,"Guest",...))) {
// do stuff
}
----------------------------------------------------------------------
-----
Peter Beckman
Internet Guy
beckman@xxxxxxxxxxx http://
www.angryox.com/
----------------------------------------------------------------------
-----
--
PHP Database Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Karl DeSaulniers
Design Drumm
http://designdrumm.com
