Don't you like my solution?
Regards,
Olavi
On Jan 25, 2010, at 9:39 PM, Karl DeSaulniers wrote:
Hi,
$req_user_level is a MySql return result and I am trying to utilize
shortened code to evaluate whither $req_user_level == 0 || 1 || 2 ||
3 || 4 || 5 || 6 || 7 || 8 || 9, if it matches a number, return the
text associated with that number.
"Guest" || "Regular User" || "Intl. User" || "Contractor" ||
"Employee" || "Sales" || "Investor" || "Human Resources" ||
"Administrator";
Karl
On Jan 25, 2010, at 1:31 PM, Olavi Ivask wrote:
Hi,
did you mean something like this?
$level_names = array("Guest", "Regular User", "Intl. User",
"Contractor", "Employee",
"Sales", "Investor", "Human Resources", "Administrator");
$user_level = $level_names[$req_user_level];
Regards,
Olavi Ivask
On Jan 25, 2010, at 9:13 PM, Karl DeSaulniers wrote:
Hello List,
Trying to learn the right way to code this line.
Can anyone tell me if I am doing this the right way?
if $req_user_level == 0 || 1 || 2 || 3 || 4 || 5 || 6 || 7 || 8 ||
9 ? "Guest" || "Regular User" || "Intl. User" || "Contractor" ||
"Employee" || "Sales" || "Investor" || "Human Resources" ||
"Administrator";
I am wanting to stray from the if(foo == bar) { routine. ;)
Thanks,
Karl DeSaulniers
Design Drumm
http://designdrumm.com
Karl DeSaulniers
Design Drumm
http://designdrumm.com
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