Quite sure this is not what you mean:
> $page = case;
> if ( $page = "contact" ) {
but instead
> $page = case;
> if ( $page == "contact" ) {
-----Mensagem original-----
De: Stut [mailto:stuttle@xxxxxxxxx]
Enviada em: sexta-feira, 22 de fevereiro de 2008 09:31
Para: Tim Daff
Cc: php-db@xxxxxxxxxxxxx
Assunto: Re: How to recognize which 'case' is being echoed by
switch statement
On 22 Feb 2008, at 11:01, Tim Daff wrote:
> <?php
> $page = case;
> if ( $page = "contact" ) {
> echo "<li
id=\"contact-active\"></li>"; }
>
> else {
> echo "<li id=\"contact\"><a
href=\"./?page=contact\">Contact</
> a></li>"; }
> ?>
$page = case; will be raising a notice which you're obviously not seeing.
So, step 1 is to edit PHP.ini on your development machine so error_reporting
is E_ALL, and display_errors is on. You'll need to restart your web server
for this change to take effect.
The case keyword is not valid outside a switch block. What you want to be
doing is comparing "contact" etc with $_GET['page'] which is the variable
the switch statement is using.
Additionally you are using a single = which is the assignment operator, so
each if statement is assigning the quoted string to $page not testing for
it. You need to use == to do that.
I would suggest you buy a book on PHP for beginners, or Google for an
introductory tutorial because these are pretty basic syntax mistakes.
-Stut
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