Am I right in thinking that exec() executes a string as a call to a
program which executes in a shell? So am I to write:
$callthis="the contents of my rsynch file";
exec($callthis);
?
John
ioannes wrote:
OK, so how would I hand over the list of files from php to the
script? And am I right that I would write the rsynch code in a text
file called anything.txt and the
rsync
at the start of the line is what calls up the rsynch program, unlike
php where you need to call it something.php - though I have never
questioned that assumption.
Or is there a way to call rsynch from the same scrpit that php is in?
I can't visualise it.
John
John
Mr Webber wrote:
The pattern in you --include-from=FILE_CONTAINING_FILENAME_PATTERNS
could be
just a list of files that you can generate from your PhpScript. Get
it now?
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