RE: Copying an image from one server to another

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Note the rsync option:

--include-from=FILE
       This  option  is  related  to  the --include option, but it specifies
a FILE that contains include patterns (one per line).  Blank
       lines in the file and lines starting with ';' or '#' are ignored.  If
FILE is -, the list will be read from standard input.

So, from a PhpScript, you manage the contents of "FILE" and then launch
rsync with the appropriate additional options.

-----Original Message-----
From: ioannes [mailto:ioannes@xxxxxxxxxxxxxx] 
Sent: Monday, February 04, 2008 12:59 PM
To: php-db@xxxxxxxxxxxxx
Subject: Re:  Copying an image from one server to another

Initially I could not find much on SCP and rsynch is about synchronising 
folders, but that is only part of the problem.  I don't want files in 
the target location that are not referenced from the target database.  I 
hold references like this

img[]=pic1.jpg&img[]=pic2.jpg

then I parse it out into the img array. 

So I want to do it from php programming and am on a shared server.  I 
may have access to the terminal for linux/unix but I am not too strong 
in that area.  So am I wrong to be still thinking of cURL?

John

Aleksandar Vojnovic wrote:
> How about sending the file via SCP? (it would be a much more safer to 
> transfer files)
>
> -Aleksander
>
> Chris wrote:
>> ioannes wrote:
>>> I am trying to:
>>>
>>> - check whether an image file exists on a server,
>>> - check whether it does not exist on another server, and if not exists
>>> - to copy from the first location to the second.
>>>
>>> I am using cURL.  First step to capture the image from the first 
>>> server.  When I return this image to the browser I get a lot of 
>>> strange characters.  So has this captured the image and what do I 
>>> use next to upload to the second server?
>>>
>>> I was trying to use file_exists and had problems referencing the 
>>> file location as "http://wwww.mysite.com/pic.jpg";.  But I know I can 
>>> also look at using readfile() and file_put_contents(), $fp = 
>>> fopen(), fputs(), fpassthru() etc.  What is best way?
>>
>> FTP.
>>
>> There's no way fopen is going to be able to write to a remote url, 
>> that'd just be such a huge security issue it's not funny.
>>
>
>

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