Peter Beckman wrote:
Because I'm trying to point out a problem with PHP, where setting a
reference when the other side is undefined or not set, PHP creates a
reference to a previously non-existent array item, just by setting a
reference. I don't think that should happen.
And? what's wrong with that. The reference can be used in the future - I
think thats why it doesnt produce any error message.
ie.
$array=array("1"=>"a","3"=>"c");
$ref=&$array["2"];
$array["2"]="b";
echo($ref);
OKi98
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