Oops, \s matches any whitespace character, so if you need only space
there you should change \s to space (this way it matches tab too).
Balazs
2006/3/31, Balazs Hegedus <balazs.hegedus@xxxxxxxxx>:
> Hi,
>
> this regex isn't perfect at all but might do the job. You should
> modify the pattern to match the year part against 2037 as a maximum
> and also don't forget to checkdate().
>
> <?php
>
> $date = '30/03/2983 12:00';
> $pattern = '[0-3][0-9]/[0|1][0-9]/[1|2][0-9]{3,3}\s[0-2][0-9]:[0-5][0-9]';
> if (preg_match("!^$pattern$!", $date) === 1) {
> echo 'date is in valid form';
> }
> else {
> echo 'date form is invalid';
> }
>
> ?>
>
> Hope it helps,
>
> Balazs
>
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