Hi, Firstly, if you are assigning the value of variable $myrow['article_title'] to $right_row, you should print $right_row and not $$right_row Because, if say, $myrow['article_title'] contained value "article1", $$right_row would look for variable $article1, which probably doesn't exist, hence no value. You could also try creating your field name simpler, something like: $tmp_fldname = $type . "_title'; $right_row = $myrow[$tmp_fldname]; This should work, I haven't tested it. Naintara -----Original Message----- From: Andrew Darby [mailto:adarby@xxxxxxxxx] Sent: Monday, February 20, 2006 10:19 PM To: php-db@xxxxxxxxxxxxx Subject: Help with Variable Variables in Array Hi, all. I can't quite figure out how to call the contents of a variable variable in a mysql_fetch_array result and was hoping someone could help . . . inside the "fetch all rows" while loop, i have the following: $right_row = "$" . myrow . "['" . $type . "_title']"; ($type is assigned elsewhere, but in this case = 'article') which outputs: $myrow['article_title'] So far so good, but i can't seem to output the value of this variable by printing $$right_row Any suggestions? TIA, Andrew -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- No virus found in this incoming message. Checked by AVG Free Edition. Version: 7.1.375 / Virus Database: 267.15.11/264 - Release Date: 17-Feb-06 -- No virus found in this outgoing message. Checked by AVG Free Edition. Version: 7.1.375 / Virus Database: 267.15.11/264 - Release Date: 17-Feb-06 -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
