Thanks Bastien,
In testing this I have added the code samples to a page and have it
working except the path statement is not correct. For now, I've just added
all the code to one page, rather than including a second page. The
statement - echo '<img src="id=$id">'; is resulting in this error - The
requested URL /id=$id was not found on this server. Any suggestions?
Thanks,
Chip
"Bastien Koert" <bastien_k@xxxxxxxxxxx> wrote on 01/25/2005 09:45:39 AM:
> the best way to do this is to move the image processing code to a
separate
> page and include it like this
>
> echo '<img src="./path/to/image.php?id=$id">';
>
> then the image page looks like this:
> <?php
>
> if($_GET['id']) {
> $id = $_GET['id'];
> // you may have to modify login information for your database server:
> @MYSQL_CONNECT("localhost","root","password");
>
> @mysql_select_db("binary_data");
>
> $query = "select bin_data,filetype from binary_data where id=$id";
> $result = @MYSQL_QUERY($query);
>
> $data = @MYSQL_RESULT($result,0,"bin_data");
> $type = @MYSQL_RESULT($result,0,"filetype");
>
> Header( "Content-type: $type");
> echo $data;
>
> };
> ?>
>
> bastien
>
>
>
> >From: Chip Wiegand <chip.wiegand@xxxxxxxxxx>
> >To: "PHP DB" <php-db@xxxxxxxxxxxxx>
> >Subject: storing images in database
> >Date: Tue, 25 Jan 2005 09:11:07 -0800
> >
> >I have stored a .jpg image in a database, then when I make a sql
statement
> >to display that image on a web page all I get is the cryptic code in
place
> >of the image. I am storing it in a row configured as a blob, mime type
> >image/jpeg and binary (using phpMyAdmin). What am I doing wrong?
> >Regards,
> >Chip
> >
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