try this??
if($row['timeout']=="")
{
echo "<input name='timeout' type='text' value='".date('H:i')."'>";
}else{
print $row["timeout"];
}
----- Original Message -----
From: <Justin.Baiocchi@xxxxxxxx>
To: <php-db@xxxxxxxxxxxxx>
Sent: Friday, August 06, 2004 10:50 AM
Subject: RE: Php if statement in a form
> Well, this works: so you were all on the right track
>
> if($row['timeout']=="")
> {
> print "<input name='timeout' type='text' value='"echo
> date('H:i')"'>";
> }else{
> print $row["timeout"];
> }
>
> But now I get a parse error on the <input> line
>
>
> -----Original Message-----
> From: Ng Hwee Hwee [mailto:hhwee@xxxxxxxxxxx]
> Sent: Friday, 6 August 2004 12:30 PM
> To: php-db@xxxxxxxxxxxxx
> Subject: Re: Php if statement in a form
>
>
> what about this?
>
> if(empty($row["timeout"]))
>
>
> ----- Original Message -----
> From: "Doug Thompson" <dthompson@xxxxxxxxxxxxx>
> To: <Justin.Baiocchi@xxxxxxxx>
> Cc: <php-db@xxxxxxxxxxxxx>
> Sent: Friday, August 06, 2004 10:18 AM
> Subject: Re: Php if statement in a form
>
>
> > if (is_null($row["timeout"]).....)
> >
> > Justin.Baiocchi@xxxxxxxx wrote:
> > > Still no joy. The parse error actually refers to the -- if
> > > ($row["timeout"] IS NULL); --- line.
> > >
> > >
>
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