Well, this works: so you were all on the right track
if($row['timeout']=="")
{
print "<input name='timeout' type='text' value='"echo
date('H:i')"'>";
}else{
print $row["timeout"];
}
But now I get a parse error on the <input> line
-----Original Message-----
From: Ng Hwee Hwee [mailto:hhwee@xxxxxxxxxxx]
Sent: Friday, 6 August 2004 12:30 PM
To: php-db@xxxxxxxxxxxxx
Subject: Re: Php if statement in a form
what about this?
if(empty($row["timeout"]))
----- Original Message -----
From: "Doug Thompson" <dthompson@xxxxxxxxxxxxx>
To: <Justin.Baiocchi@xxxxxxxx>
Cc: <php-db@xxxxxxxxxxxxx>
Sent: Friday, August 06, 2004 10:18 AM
Subject: Re: Php if statement in a form
> if (is_null($row["timeout"]).....)
>
> Justin.Baiocchi@xxxxxxxx wrote:
> > Still no joy. The parse error actually refers to the -- if
> > ($row["timeout"] IS NULL); --- line.
> >
> >
--
PHP Database Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
