Re: How to define array variable while accessing it ???

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Well, IMHO you shouldn't do in-string variables as you never know if
it will work. In this case, it won't YOu should do something like
this:

$query='delete from feedback where id='.$delete[$i];

Single quotes tell PHP not to look for variables in the string. A
period concatenates. There's actually a better solution, too:

$query='delete from feedback where
id="'.mysql_real_escape_string($delete[$i]).'"';

On Tue, 29 Jun 2004 00:06:24 -0700 (PDT), Rinku <rinku_pgsql@xxxxxxxxx> wrote:
> 
> Actually I want to know how to access the variable
> after defining it.
> Like :
> $query="delete from feedback where id=$delete[$i]";
>             $deleteresult=mysql_query($query) or
> die("Unable to delete");
> 
> But here I am not getting any value in
> "$delete[$i]"-(here $i is 0,1,2,3)
> 
> So what to do to access it ?
> I cant access the value even by $_POST['$delete[$i]']
> 
> Can any of you suggest me the sollution ?
> 
> Rinku
> 
> 
> --- Torsten Roehr <roehr@xxxxxxxxxxx> wrote:
> > "Matt M." <h.dudeness@xxxxxxxxx> wrote in message
> > news:7d458020040628114862c2d150@xxxxxxxxxxxxxxxxx
> > > >              <TD><DIV ALIGN="CENTER"> <input
> > type="checkbox" name="<?
> > printf("chk_arr[%d]",$i); ?>" value="<?=$row[0]?>"
> > ></DIV></TD>
> > >
> > > setup your checkbox something like this:
> > >
> > > <input type="checkbox" name="delete[]"
> > value="<?=$row[0]? />
> > >
> > > php will treat this as an array
> >
> > The closing php tag and quote of the value attribute
> > was missing:
> >
> > <input type="checkbox" name="delete[]" value="<?=
> > $row[0] ?>" />
> >
> > Regards, Torsten Roehr
> >
> > --
> > PHP Database Mailing List (http://www.php.net/)
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> >
> >
> 
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