Re: help with consecutive numbers in db

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Hello redhat,

      Hey... look at this:

CREATE TABLE `testip` (
  `id` int(10) unsigned NOT NULL auto_increment,
  `theip` varchar(100) NOT NULL default '',
  PRIMARY KEY  (`id`),
  UNIQUE KEY `theip` (`theip`)
) TYPE=MyISAM AUTO_INCREMENT=7 ;
      

SELECT theip, SUBSTRING_INDEX( theip, ".", 1 ) *1 AS one,
substring_index( SUBSTRING_INDEX( theip, ".", 2 ) , ".", -1 ) *1 AS two,
substring_index( SUBSTRING_INDEX( theip, ".", 3 ) , ".", -1 ) *1 AS three,
SUBSTRING_INDEX( theip, ".", -1 ) *1 AS four
FROM `testip` 
ORDER BY one, two, three, four

And you have all ip's ordered by number...
so you can do:
<?php
   $Result=mysql_query("Select theip, SUBSTRING.....", $db);
   $lastgroup="0.0.0";
   $key=255;
   while(list($theIP,$one,$two,$three,$four)=mysql_fetch_row($Result)) {
      if ($lastgroup<>"$one.$two.$three") {
         while ($key<80) echo "$lastgroup." . ($key++) . " is free<br>\n";
         $key=1;
      }
      while ($key<($four*1)) echo "$one.$two.$three." . ($key++) . " is free<br>\n";
      echo "$one.$two.$three.$four IS NOT FREE<br>\n";
      $lastgroup="$one.$two.$three";
      $key++;
   }
   while ($key<80) echo "$lastgroup." . ($key++) . " is free<br>\n";
?>

P.S. I DONT KNOW IF THIS IS TOO SLOW.. you might test..

-- 
Best regards,
 Pablo

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