The reason for this is due to the variable "$action" not having any relation
to the action. Therefore, you should use the following if/then statement:
if ($submit !== '') {
// STATEMENTS
}
The "submit" name/value pair variable passed via your form is a named
variable that possesses the value of "Submit Query", so you could
essentially make the if/then statement be:
if ($submit == 'Submit Query') {
// STATEMENTS
}
However, you will have to ensure that the "register_globals" directive has a
value of "Yes" in your PHP.ini configuration file.
If you're unsure of the value of your "register_globals" directive, create
and execute the following script:
<?
phpinfo();
?>
This function will state all of the environment variables associated with
your install of PHP on your server.
Hope this helps...
-Zak
On 6/20/04 5:18 AM, "Rinku" <rinku_pgsql@xxxxxxxxx> wrote:
> Actually I want to use the function like
> if($action="Login")
> {
> Statements;
> }
> But here I am not getting any value in $action even I click on it.
> When I was using Linux at that time I had not this kind of problem.
>
> Rinku
> Marvin Hechanova <mhechanova@xxxxxxxxx> wrote:
> You have to assign values to your name and action
> e.g.
>
> [input] " value=Rinku>
> [input] " type=submit value="Submit Query"
> value="Login">
>
> but why would you want to print the results?
>
>
> On Sun, 20 Jun 2004 04:22:59 -0700 (PDT), Rinku wrote:
>>
>> Dear All,
>>
>> I have installed PHP on WinXp. I am using MySql as Backend on Apache server.
>> Now the problem is......
>> I am writing this code :
>>
>>
>>
>>
>>
>>
>>
>>
>> [input]
>> [input]
>>> print $action;
>> print $Name;
>> ?>
>>
>>
>>
>> Here I should get output as LoginRinku
>> But I am getting nothing.
>>
>> Can any of you guide me on this........?
>>
>> Regards,
>> Rinku
>>
>>
>> ---------------------------------
>> Do you Yahoo!?
>> New and Improved Yahoo! Mail - Send 10MB messages!
>
>
> ---------------------------------
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